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12x^2+1=-7x
We move all terms to the left:
12x^2+1-(-7x)=0
We get rid of parentheses
12x^2+7x+1=0
a = 12; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·12·1
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*12}=\frac{-8}{24} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*12}=\frac{-6}{24} =-1/4 $
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